Exercise 5 solutions

print "Fahrenheit", "Celsius", "C"
for i in range(0,100,10):
        print "%10.2f %7.2f %6.2f" % (i, (i-32.)*5./9., (i-30)/2.0)

disp(['Fahrenheit Celsius C']);
for i=0:10:90
  disp(sprintf('%10.2f %7.2f %6.2f', i, (i-32)*5/9, (i-30)/2));
end;

cat("Fahrenheit", "Celsius", "C\n")
for (i in seq(0,90,10)) {
		cat(sprintf("%10.2f %7.2f %6.2f\n", i, (i-32)*5/9, (i-30)/2))
}

// compile with: gcc -o e05 e05.c

#include <stdio.h>

int main(int argc, char *argv[]) {

  printf("Fahrenheit Celsius C\n");
  int i;
  for (i=0; i<=90; i+=10) {
    printf("%10.2f %7.2f %6.2f\n", (double) i, ((double)i-32)*5/9, ((double)i-30)/2);
  }

  return 0;
}